(4x^2-18x+20)/(x+3)

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Solution for (4x^2-18x+20)/(x+3) equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(4*x^2-(18*x)+20)/(x+3) = 0

(4*x^2-18*x+20)/(x+3) = 0

4*x^2-18*x+20 = 0

2*(2*x^2-9*x+10) = 0

2*x^2-9*x+10 = 0

DELTA = (-9)^2-(2*4*10)

DELTA = 1

DELTA > 0

x = (1^(1/2)+9)/(2*2) or x = (9-1^(1/2))/(2*2)

x = 5/2 or x = 2

2*(x-2)*(x-5/2) = 0

(2*(x-2)*(x-5/2))/(x+3) = 0

( x-2 )

x-2 = 0 // + 2

x = 2

( x-5/2 )

x-5/2 = 0 // + 5/2

x = 5/2

x in { 2, 5/2 }

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